Making Sense of NoSQL: A guide for managers and the rest of by Dan McCreary, Ann Kelly

By Dan McCreary, Ann Kelly

Summary

Making experience of NoSQL essentially and concisely explains the recommendations, beneficial properties, advantages, capability, and obstacles of NoSQL technologies.

Using examples and use circumstances, illustrations, and simple, jargon-free writing, this advisor exhibits how one can successfully gather a NoSQL way to substitute or increase the normal RDBMS you've now.

About this Book

If you need to comprehend and maybe begin utilizing the hot facts garage and research applied sciences that transcend the SQL database version, this e-book is for you. Written in undeniable language compatible for technical managers and builders, and utilizing many examples, use situations, and illustrations, this publication explains the techniques, gains, advantages, strength, and barriers of NoSQL.

Making experience of NoSQL begins via evaluating popular database suggestions to the hot NoSQL styles that increase or exchange them. Then, you'll discover case reviews on vast info, seek, reliability, and enterprise agility that observe those new styles to today's company difficulties. You'll see how NoSQL structures can leverage the assets of contemporary cloud computing and multiple-CPU info facilities. the ultimate chapters help you opt for the best NoSQL applied sciences to your personal needs.

Managers and builders will welcome this lucid review of the aptitude and functions of NoSQL technologies.

What's Inside

• NoSQL facts structure patterns;
• NoSQL for giant data;
• seek, excessive availability, and security;
• settling on an architecture.

About the Authors

Dan McCreary and Ann Kelly lead an self sustaining education and consultancy enterprise taken with NoSQL recommendations and are cofounders of the NoSQL Now! Conference.

Table of Contents

PART 1 INTRODUCTION
• NoSQL: It's approximately making clever choices
• NoSQL concepts

PART 2 DATABASE PATTERNS
• Foundational info structure patterns
• NoSQL info structure patterns
• local XML databases

PART three NOSQL SOLUTIONS
• utilizing NoSQL to regulate monstrous data
• discovering info with NoSQL search
• construction high-availability recommendations with NoSQL
• expanding agility with NoSQL

PART four complicated TOPICS
• NoSQL and useful programming
• defense: maintaining info on your NoSQL systems
• choosing the right NoSQL resolution

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Additional info for Making Sense of NoSQL: A guide for managers and the rest of us

Sample text

Which type of variable do you create in the PL/SQL block to retrieve all the rows and columns using a single select statement from the emp table? A: PL/SQL table of records. 123. Examine the employee table. ID NO 7 6 4 3 2 5 1 8 LAST_NAME Brown Wargner southall chiazza limber goldberg lomberg oliver FIRST_NAME Terry Julie david mike john Kelvin susan tracey SALARY 30000 25000 50000 32000 DEPT_NO 255 233 102 145 233 55000 145 You attempt to query the database with this command: SELECT dept_no,last_name,SUM(salary) FROM employee WHERE salary<50000 GROUP BY dept_no ORDER BY last_name; Which clause causes an error?

GROUP BY (deptno)a, (SELECT COUNT(*)total_count,SUM(sal)total_sal. emp) b; 109. In which situation would you use an outer query? A: The employee table column corresponding to the region table contain null values for rows that need to be displayed. 110. You attempt to query the database with this command: SELECT name,salary FROM employee WHERE salary= (SELECT salary FROM employee WHERE last_name= ‘Wagner’ OR dept_no=233) Why could this statement cause an error? A: A multiple row subquery is used with a single row comparison operator.

Examine the table instance chart for the patient table. Column name Key type Nulls/Unique FK table FK column Data type Length id_number last_name PK NN, U NN NUM 10 first_name Birth_date doctor_id NN VARCHAR2 25 VARCHAR2 25 DATE DOCTOR ID_NUMBER NUM 10 You need to create the patient_id_seq sequence to be used with the patient table’s primary key column. The sequence will begin with 1000, have a maximum value of 999999999 never reuse any number an increment by 1. Which statement would you use to complete this task?

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