Geometry and topology: manifolds, varieties, and knots by Mccrory

By Mccrory

McCrory C., Shifrin T. (eds.) Geometry and topology ()(ISBN 0824776216)(T)(355s)

Show description

Read Online or Download Geometry and topology: manifolds, varieties, and knots PDF

Similar topology books

Topology of Singular Fibers of Differentiable Maps

The amount develops a radical conception of singular fibers of ordinary differentiable maps. this is often the 1st paintings that establishes the foundational framework of the worldwide learn of singular differentiable maps of unfavorable codimension from the perspective of differential topology. The e-book includes not just a normal idea, but additionally a few particular examples including a few very concrete purposes.

A First Course in Algebraic Topology

This self-contained creation to algebraic topology is acceptable for a couple of topology classes. It contains approximately one sector 'general topology' (without its ordinary pathologies) and 3 quarters 'algebraic topology' (centred round the basic workforce, a simply grasped subject which provides a good suggestion of what algebraic topology is).

Additional resources for Geometry and topology: manifolds, varieties, and knots

Sample text

1. Lifting maps We next turn to the following problem: if p : Z → X is a covering map, and f : Y → X is a map, when can we expect there to be a lift f of f ; that is a map f : Y → Z such that pf = f . 1. 5. Painting sides of a surface It will be convenient to adopt the following convention: a commutative diagram of the form f Y −−−→ Z  p f Y −−−→ X should be thought of as a triangle. 5. Let p : (Z, z0 ) → (X, x0 ) be a based covering map, and f : Y → X a map from a connected space. Then, if there is a lift f of (a map making the diagram above commute), it is unique.

To start you off, notice that in rule [2] (cancellation of . . aa−1 . . we lose 1 edge and 1 vertex, preserving χ. The other rules are similar. Under barycentric subdivision, let K be the combinatorial surface obtained from K. Then α0 (K ) = α0 (K) + α1 (K) + α2 (K) (one new vertex for each edge and each triangle in K), α1 (K ) = 2α1 (K) + 6α2 (K) (six new edges in each triangle of k and each edge of k split into two), and α2 (K ) = 6α2 (K). It follows that χ(K ) = α0 (K ) − α1 (K ) + α2 (K ) = α0 (K) + α1 (K) + α2 (K) − 2α1 (K) − 6α2 (K) + 6α2 (K) = α0 (K) − α1 (K) + α2 (K) = χ(K).

BXddb−1 · · · −→ . . bXe−1 be−1 . . , and then by [3], . . bXe−1 be−1 · · · −→ . . bbeX −1 e−1 . . That is, we have reduced the original pair separated by d1 d1 . . dn dn dd to a similar pair separated by −1 −1 −1 d−1 n dn . . d1 d1 . 3. 20. Pairs of the kind . . b . . b−1 . . After n such steps, the symbol has the form . . bddb−1 · · · −→ . . be−1 be−1 . . (by the same cut and paste with X = ∅), and then . . be−1 be−1 · · · −→ . . f f . . by [1], with f = be−1 . Notice that the existence of such a pair .

Download PDF sample

Rated 4.17 of 5 – based on 29 votes